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72 lines
2.2 KiB
72 lines
2.2 KiB
1 month ago
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def find_title_and_path(data, key, path=None, level=0):
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if path is None:
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path = []
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if 'key' in data and data['key'] == key:
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# 当前层级的title加入路径
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path.append((data['title']))
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return data['title'], level, path
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elif 'children' in data:
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for child in data['children']:
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title, child_level, updated_path = find_title_and_path(child, key, path + [(data['title'])], level + 1)
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if title is not None:
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return title, child_level, updated_path
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return None, -1, path
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# 示例数据
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data = {
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"title": "数据标准",
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"key": "100",
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"value": "100",
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"dscatalog_parent_id": "0",
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"children": [
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{
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"title": "基础标准",
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"key": "101",
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"value": "101",
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"dscatalog_parent_id": "100",
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"children": [
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{"title": "客户", "key": "104", "value": "104", "dscatalog_parent_id": "101"},
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{"title": "客户基础信息", "key": "105", "value": "105", "dscatalog_parent_id": "101"},
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{"title": "账户", "key": "106", "value": "106", "dscatalog_parent_id": "101"},
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{"title": "账户基础信息", "key": "107", "value": "107", "dscatalog_parent_id": "101"}
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]
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},
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{
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"title": "指标标准",
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"key": "102",
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"value": "102",
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"dscatalog_parent_id": "100",
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"children": [
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{"title": "风险", "key": "103", "value": "103", "dscatalog_parent_id": "102"}
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]
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}
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]
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}
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# 测试函数
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key_to_find = "106"
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title, level, path = find_title_and_path(data, key_to_find)
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if {level} == 2 :
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std_pri_clas = path[0]
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std_scd_clas = path[1]
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std_thre_clas = path[2]
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if {level} == 1 :
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std_pri_clas = path[0]
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std_scd_clas = path[1]
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std_thre_clas = None
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if {level} == 0 :
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std_pri_clas = path[0]
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std_scd_clas = None
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std_thre_clas = None
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else:
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pass
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# if title:
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# print(f"The title with key '{key_to_find}' is '{title}' and it is at level {level}.")
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# print("Path:")
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# for title in path:
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# print(f"{title}")
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# else:
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print(f"No title found for key '{key_to_find}'.")
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